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2(x^2+7x-330)=0
We multiply parentheses
2x^2+14x-660=0
a = 2; b = 14; c = -660;
Δ = b2-4ac
Δ = 142-4·2·(-660)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-74}{2*2}=\frac{-88}{4} =-22 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+74}{2*2}=\frac{60}{4} =15 $
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